访谈

解读Trafford的Broadoak学校的结果:第一组数字= A * -E的总数通过括号中的A * -C水平

第二组数字=括号1-4中新的9-1等级的总数

L Barlow 6(6),3(3); D Beesley 4(1),3(2); L Bellamy 4(0),3(0); T Bowen 3(0),3(0); M Boygle 3(2),3(3); D桥6(6),3(3); C Brooke 6(0),3(1); L Burgess 6(4),3(2); L Cook 4(1),3(0); E Craveiro 6(5),3(2); L Derrick 5(4),3(3); R Drummond 4(0),3(0); M Evans 4(1),3(2); S Fitzgerald 4(0),3(0);加纳5(0),3(1); B Gorton 4(1),3(1); L Gorton 5(4),3(3); S Gorton 4(2),3(2); Lee Graham 3(3),3(2); Lu Graham 5(0),3(0); C Gregson 2(0),3(0); K saint 6(0),3(1); C Hand 5(2),3(3); C Havern 3(0),3(0); J Hodgkinson 6(3),3(2 C Inkersole 4(0),3(1); E Joughen 6(6),3(3); G Kabouadiko 7(7),3(3); C Littler 2( 0),2(0); C Lloyd 5(1),3(1); J Luciano 5(4),3(3); J Lyth 4(1),3(0); J Maas 4(0) ,3(3); Z Mates 5(5),3(3); J McVety 6(6),3(3); Mellor-Gee 4(0),3(0); D Newton 5(3), 3(1); K O'Mary 5(3),3(3); S Palmer 4(3),3(3); L Phythian 4(2),3(0); T Ralph 5(4), 3(3); C Renshaw 4(1),3(2); A Sandham 5(1),3(0); K Sherriff 3(0),2(0); J Sikking 3(0),3( 1); E Smith 5(3),3(3); J Smith 7(7),3(3); L Taylor 6(6),3(3); S Walsh 4(0),3(1) ; K Weekes 4(3),3(3); J Wood 6(6),3(3); T Woolstencroft 6(6),3(3); W Zagorowicz 5(3),3(3); S Zaouri 5(4),3(2)